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Angle Chasing

Maths · Year 9
Year 9
Lesson Guide
Explanation
Two parallel lines with a bent line between them is a favourite competition picture. The trick is to draw a third line through the bend, parallel to the other two. Now the angle at the bend splits into two parts. The upper part is alternate to the forty degree angle at A, so it is forty degrees. The lower part is alternate to the sixty five degree angle at C, so it is sixty five degrees. So x is forty plus sixty five, which is one hundred and five degrees. Whenever a line bends between parallels like this, the bend angle is the sum of the two angles it makes with the parallel lines.
Your Turn
A bent line between two parallel lines makes 30° with the top line and 72° with the bottom line, bending as in the picture. Find the bend angle. Check: 30 + 72 = 102°.
Watch Out
There is no triangle in this picture, so 180 − (40 + 65) = 75° is wrong. Draw the extra parallel line first and use alternate angles.
Explanation
In triangle A B C the ticks show that A B equals A C, so the angles opposite those sides, at B and at C, are equal. The angle at A is forty degrees, so the other two share one hundred and forty degrees: seventy each. Now extend B C to D. Angle A C D sits on a straight line with the seventy degree angle, so it is one hundred and ten degrees. There is a shortcut called the exterior angle theorem: an exterior angle of a triangle equals the sum of the two interior angles opposite it. Forty plus seventy is one hundred and ten. In competition problems you will use this shortcut again and again.
Your Turn
An isosceles triangle has apex angle 50°. Find a base angle and the exterior angle next to it. Check: (180 − 50) ÷ 2 = 65°, and 180 − 65 = 115°.
Watch Out
The equal angles are opposite the equal SIDES: at B and C here, not at A. Look at which sides carry the ticks before you decide which angles match.
Explanation
Pick one corner of a polygon and draw every diagonal from it. A hexagon splits into four triangles, so its interior angles add to four times one hundred and eighty, which is seven hundred and twenty degrees. In general, a polygon with n sides splits into n minus two triangles, so its interior angles add to n minus two, times one hundred and eighty. The exterior angles are even easier: walk all the way round any polygon and you turn through one full turn, three hundred and sixty degrees. So each exterior angle of a regular octagon is three hundred and sixty divided by eight, forty five degrees, and each interior angle is one hundred and eighty minus forty five, one hundred and thirty five. Working backwards, if each exterior angle is twenty four degrees, the polygon has three hundred and sixty divided by twenty four, which is fifteen sides.
Your Turn
Each interior angle of a regular polygon is 160°. How many sides does it have? Check: the exterior angle is 20°, and 360 ÷ 20 = 18 sides.
Watch Out
The interior sum is (n − 2) × 180°, not n × 180°: a hexagon gives 720°, not 1080°. To find n, go through the exterior angle; it is much quicker.
Explanation
Here is a five-pointed star whose points are not all the same. The surprising fact is that its five tip angles always add to one hundred and eighty degrees. Here is why. Look at the shaded triangle with tip A at the top. Each of its two bottom corners is an exterior angle of a small triangle, so each one equals the sum of two other tips. That means the three angles of the shaded triangle hold all five tips between them, and the angles of a triangle add to one hundred and eighty. So thirty two plus thirty six plus forty one plus forty five plus x is one hundred and eighty. The four known tips make one hundred and fifty four, so x is twenty six degrees.
Your Turn
Four tips of a five-pointed star are 25°, 40°, 38° and 32°. Find the fifth tip. Check: 180 − 135 = 45°.
Watch Out
The tips add to 180°, not 360° and not 540°. 540° belongs to the pentagon in the middle of the star, not to the tips.
Explanation
Regular polygons fit together around a point with no gap only if their interior angles add to exactly three hundred and sixty degrees. A square has ninety degrees. A regular octagon has one hundred and thirty five. Ninety plus one hundred and thirty five plus one hundred and thirty five is three hundred and sixty, so a square and two octagons fit perfectly. That is the pattern on many tiled floors. To find a missing polygon, work out the gap it has to fill, turn that interior angle into an exterior angle, and divide it into three hundred and sixty. Quiz and exercises now.
Your Turn
An equilateral triangle and two copies of one regular polygon meet at a point with no gap. Which polygon? Check: (360 − 60) ÷ 2 = 150°, exterior 30°, so 12 sides.
Watch Out
Add INTERIOR angles at a point. Adding exterior angles (90 + 45 + 45 = 180) makes it look as if the shapes do not fit.
📌 Key Points — this lesson in a nutshell
  • Parallel lines: alternate angles are equal, corresponding angles are equal, co-interior angles add to 180°. At a bend between two parallel lines, the bend angle is the sum of the two alternate angles — draw a third parallel line through the bend.
  • Isosceles triangle: the angles opposite the equal sides are equal. Exterior angle theorem: an exterior angle of a triangle equals the sum of the two interior opposite angles.
  • A polygon with n sides: interior angles add to (n − 2) × 180°; exterior angles always add to 360°, so a regular polygon has exterior angle 360° ÷ n and n = 360 ÷ exterior.
  • The five tip angles of any five-pointed star add to 180°.
  • Regular polygons fit around a point only when their interior angles add to exactly 360°.
Step 1: Introduction
Step 1 of 5
ℓ ∥ m: find the bend angle x 40°65°40°65°xABCℓm 1upper part: alternate to A40°2lower part: alternate to C65°3x = 40° + 65°105° Draw a parallel line through the bend.Each part is alternate to an angleon ℓ or on m. Then add.
AB = AC: base angles and the exterior angle 40°70°70°110°ABCD 1base angles: (180 − 40) ÷ 270°2straight line at C: 180 − 70110°3or: 40 + 70 (exterior angle)110° Exterior angle theorem:angle ACD = angle A + angle B.One step instead of two.
Angles in polygons 1234 1hexagon: 4 triangles × 180720°2n sides: (n − 2) × 180interior sum3regular octagon: 360 ÷ 8exterior 45°4interior: 180 − 45135°5exterior 24°: 360 ÷ 2415 sides
Five tips of a star: find x xA36°41°32°45° 1five tips always add to180°232 + 36 + 41 + 45154°3x = 180 − 15426° Why: in the shaded triangle, eachbottom corner is an exterior angle,equal to the sum of two other tips.
A square and two regular octagons 90°135°135° 1square90°2regular octagon: 180 − 360 ÷ 8135°390 + 135 + 135360° ✓ Missing polygon? Find the gap,turn it into an exterior angle,then divide it into 360.
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