T

Linear Inequalities

Maths · Year 9
Year 9
Lesson Guide
Explanation
An inequality is solved the same way as an equation, by doing the same thing to both sides. For three x plus five is less than twenty, subtract five from both sides: three x is less than fifteen. Divide both sides by three: x is less than five. The answer is not one number but a whole range: every number below five. Test one: x equals four gives seventeen, and seventeen is less than twenty. On the number line, draw an open circle at five, because five itself is not included, and shade everything to the left.
Your Turn
Solve 4x − 3 ≥ 13. Check: 4x ≥ 16, so x ≥ 4 (closed circle at 4).
Watch Out
The answer is a range, not x = 5. Keep the inequality sign in every line.
Explanation
Here is the one rule that is different from equations. Two is less than five. Multiply both by negative one and you get negative two and negative five, but now negative two is the bigger one. The order has flipped. So whenever you multiply or divide both sides by a negative number, you must reverse the inequality sign. For negative two x is greater than six, divide both sides by negative two and reverse: x is less than negative three. Test it: x equals negative four gives eight, and eight is greater than six.
Your Turn
Solve −3x ≤ 12. Check: divide by −3 and reverse: x ≥ −4.
Watch Out
Only multiplying or dividing by a negative reverses the sign. Adding or subtracting a negative never does.
Explanation
With x on both sides, you can avoid dividing by a negative altogether. In seven minus two x is greater than or equal to three x minus eight, add two x to both sides: seven is at least five x minus eight. Add eight: fifteen is at least five x. Divide by five, which is positive, so no flip: three is at least x. Read that from the x's point of view: x is less than or equal to three. If you had gathered the x's on the left instead, you would get negative five x is at least negative fifteen, and dividing by negative five with the sign reversed gives the same answer.
Your Turn
Solve 10 − x > x + 2. Check: 8 > 2x, so 4 > x, which is x < 4.
Watch Out
3 ≥ x means x ≤ 3. When you swap the sides, the sign must point the other way.
Explanation
A range with two ends, like negative two is less than or equal to x, which is less than three, is drawn with a circle at each end. Negative two has a closed circle, because it is included. Three has an open circle, because it is left out. The integers in the range are negative two, negative one, zero, one and two. That is five integers. Three is not on the list, because of its open circle.
Your Turn
List the integers with −1 < x ≤ 2. Check: 0, 1, 2 (−1 is left out).
Watch Out
Open circle, end left out; closed circle, end included. The end values are where marks are lost.
Explanation
A compound inequality has three parts, like negative three is less than two x plus one, which is less than or equal to nine. Do the same thing to all three parts. Subtract one: negative four is less than two x, which is at most eight. Divide all three parts by two: negative two is less than x, which is at most four. So x is between negative two and four, with negative two left out and four included. The integers are negative one, zero, one, two, three and four. If you ever divide all three parts by a negative, reverse both signs. Quiz and exercises now.
Your Turn
Solve 1 ≤ 3x − 2 < 10. Check: 3 ≤ 3x < 12, so 1 ≤ x < 4.
Watch Out
Change all three parts. Subtracting 1 from the middle only gives −3 < 2x ≤ 9, which is wrong.
📌 Key Points — this lesson in a nutshell
  • Solve an inequality like an equation: add, subtract, multiply or divide both sides.
  • Multiply or divide both sides by a negative number and you must reverse the sign: −2x > 6 gives x < −3.
  • On a number line, an open circle means the end is left out (<, >); a closed circle means it is included (≤, ≥).
  • A compound inequality like −3 < 2x + 1 ≤ 9 has three parts: do the same thing to all three.
Step 1: Introduction
Step 1 of 5
3x + 5 < 20 1subtract 5 from both sides3x < 152divide both sides by 3x < 53test x = 4: 3(4) + 5 = 1717 < 20 ✓ −1012345678 x < 5: every number below 5, but not 5 itself.Open circle at 5, shading to the left.
−2x > 6 12 < 5, but multiply both by −1−2 > −52divide both sides of −2x > 6 by −2REVERSE the sign3sox < −34test x = −4: −2(−4) = 88 > 6 ✓ −7−6−5−4−3−2−1012 Multiply or divide by a NEGATIVE: flip the sign.
7 − 2x ≥ 3x − 8 1add 2x to both sides7 ≥ 5x − 82add 8 to both sides15 ≥ 5x3divide by 5 (positive: no flip)3 ≥ x4read it from the xx ≤ 3 Keep the x-term positive and you never have to flip.Other way: −5x ≥ −15, divide by −5 and reverse: x ≤ 3.3 ≥ x and x ≤ 3 say the same thing.
−2 ≤ x < 3 −4−3−2−1012345 1closed circle at −2−2 is included2open circle at 33 is left out3integers in the range−2, −1, 0, 1, 2 That is 5 integers. Count the closed end; skip the open end.
−3 < 2x + 1 ≤ 9 1subtract 1 from all three parts−4 < 2x ≤ 82divide all three parts by 2−2 < x ≤ 43integers−1, 0, 1, 2, 3, 4 −4−3−2−10123456 Do the same thing to ALL THREE parts.Dividing by a negative here reverses BOTH signs.Quiz and exercises now.
Was this lesson helpful? Rate this Course
Discussion
Loading comments...