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Formulas: Substitute and Rearrange

Maths · Year 9
Year 9
Lesson Guide
Explanation
To substitute into a formula, replace each letter with its value, and put every value in brackets, especially a negative one. In v equals u plus a t, with u equal to twenty, a equal to negative three and t equal to four, write v equals twenty plus, in brackets, negative three, times four. a t means a times t, and multiplication comes before addition, so work out negative three times four first: negative twelve. Then twenty plus negative twelve is eight. So v equals eight.
Your Turn
Find v when u = −5, a = 2 and t = 6. Check: v = −5 + 12 = 7.
Watch Out
Multiply before you add. 20 + (−3)(4) is 20 − 12 = 8, not 17 × 4 = 68.
Explanation
Here is the area of a trapezium: A equals one half, times a plus b in brackets, times h. With a equal to six, b equal to ten and h equal to five, work out the bracket first: six plus ten is sixteen. Half of sixteen is eight. Eight times the height, five, is forty. So the area is forty square units. The bracket is the whole point: the two parallel sides are added before anything else happens to them.
Your Turn
Find A when a = 3, b = 9 and h = 4. Check: ½ × 12 × 4 = 24.
Watch Out
Do the bracket first. ½ × 6 + 10 × 5 = 53 is wrong, because it ignores the bracket.
Explanation
To change the subject, look at how the formula builds the answer from the letter you want. Starting from a, the formula multiplies by t and then adds u to get v. To get back to a, undo those steps in reverse order: first subtract u from both sides, giving v minus u equals a t, then divide both sides by t. So a equals v minus u, all over t. Check with numbers: if u is two, a is three and t is four, then v is fourteen, and fourteen minus two, over four, is three.
Your Turn
Make t the subject of v = u + at. Check: v − u = at, so t = (v − u)/a.
Watch Out
Subtract u before you divide. v/t − u is a different formula: the u was never divided by t.
Explanation
Some subjects take several steps. To make b the subject of A equals a half, a plus b, times h, first clear the half by multiplying both sides by two: two A equals a plus b, times h. The bracket a plus b stays together as one group while you divide both sides by h: two A over h equals a plus b. Only now can you subtract a: b equals two A over h, minus a. Check with the trapezium from before: two times forty over five is sixteen, minus six is ten, and b was ten.
Your Turn
Make h the subject of A = ½(a + b)h. Check: 2A = (a + b)h, so h = 2A/(a + b).
Watch Out
Do not split the bracket early. Subtracting a before dividing by h gives (2A − a)/h, which is wrong.
Explanation
Watch the sign when the subject has a minus in front of it. In y equals five minus three x, subtract five from both sides: y minus five equals negative three x. Dividing by negative three gives x equals y minus five over negative three, which tidies to five minus y, all over three. A neater way is to add three x to both sides first, so the x-term is positive: three x plus y equals five, then three x equals five minus y. Either way, x equals five minus y, over three. Check: x equals one gives y equals two, and five minus two, over three, is one. Quiz and exercises now.
Your Turn
Make x the subject of y = 7 − 2x. Check: 2x = 7 − y, so x = (7 − y)/2.
Watch Out
The minus belongs to the 3x. (y − 5)/3 has lost it; the answer is (5 − y)/3.
📌 Key Points — this lesson in a nutshell
  • To substitute, put each value in brackets — especially negatives — then follow the order of operations.
  • To change the subject, undo the operations in reverse order, doing the same thing to both sides.
  • The new subject must end up alone on one side; anything in a bracket or on top of a fraction stays together as a group.
  • Check a rearranged formula by putting the same numbers into both versions.
Step 1: Introduction
Step 1 of 5
v = u + at with u = 20, a = −3, t = 4 1write the formulav = u + at2brackets round each valuev = 20 + (−3)(4)3multiply firstv = 20 + (−12)4then addv = 8 Put every substituted value in brackets.Multiply before you add: at means a × t.A negative a means the speed is dropping.
A = ½(a + b)h with a = 6, b = 10, h = 5 1write the formulaA = ½(a + b)h2the bracket firsta + b = 163half of 1684times the heightA = 8 × 5 = 40 This is the area of a trapezium.Add the parallel sides BEFORE halving and multiplying.½(a + b)h is not ½a + b × h.
Make a the subject of v = u + at build v a× tat+ uv undo v− uv − u÷ ta Undo in reverse order: subtract u FIRST, then divide by t.a = (v − u)/tCheck: u = 2, a = 3, t = 4 gives v = 14, and (14 − 2)/4 = 3 ✓
Make b the subject of A = ½(a + b)h 1multiply both sides by 22A = (a + b)h2divide both sides by h2A/h = a + b3subtract a from both sidesb = 2A/h − a4check: a = 6, h = 5, A = 4080/5 − 6 = 10 ✓ (a + b) stays together until the h is gone.Clear the ½ first by doubling both sides.b appears once, alone, on one side.
Make x the subject of y = 5 − 3x 1subtract 5 from both sidesy − 5 = −3x2divide both sides by −3x = (y − 5)/(−3)3tidy the signsx = (5 − y)/34check: x = 1 gives y = 2(5 − 2)/3 = 1 ✓ Or add 3x to both sides first: 3x + y = 5, so 3x = 5 − y.Either way, x = (5 − y)/3.Quiz and exercises now.
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