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Surface Area of Prisms

Maths · Year 9
Year 9
Lesson Guide
Explanation
Surface area is the total area of all the faces of a solid. Unfold the box into its net and you can see all six faces at once. They come in three matching pairs. The top and the bottom are each six by four, which is twenty four, so together they make forty eight. The front and the back are each six by three, eighteen, so together thirty six. The two ends are each four by three, twelve, so together twenty four. Add the pairs: forty eight plus thirty six plus twenty four is one hundred and eight square centimetres. As a formula, the surface area is two times l w plus l h plus w h.
Your Turn
Find the surface area of a closed box 5 cm × 2 cm × 2 cm. Check: 2(10 + 10 + 4) = 48 cm2.
Watch Out
Every face has a partner. Adding 24 + 18 + 12 = 54 counts only three of the six faces.
Explanation
A triangular prism has five faces: two triangles at the ends and three rectangles joining them. The triangle here has sides three, four and five, with the right angle between the three and the four. Each triangle has area one half times four times three, which is six, so the two ends make twelve. Each rectangle is one side of the triangle times the length of the prism, ten. That gives forty, thirty and fifty. Do not forget the sloping one: it is the five centimetre side times ten. The total is twelve plus forty plus thirty plus fifty, which is one hundred and thirty two square centimetres.
Your Turn
A prism has a right-angled triangle with sides 6, 8 and 10 cm and is 5 cm long. Check: 2 × 24 + 5 × (6 + 8 + 10) = 48 + 120 = 168 cm2.
Watch Out
The triangles need the ½. Using 4 × 3 = 12 for each one counts each triangle twice.
Explanation
This prism has a triangle with base twenty four and height five, but the sloping sides are not given. The height cuts the triangle into two right-angled triangles, each with a base of twelve and a height of five. By Pythagoras, the slant squared is twelve squared plus five squared, which is one hundred and sixty nine, so the slant is thirteen. Now count every face. The two triangles give two times one half times twenty four times five, which is one hundred and twenty. The base rectangle is twenty four by twenty, four hundred and eighty. The two sloping rectangles are each thirteen by twenty, so together five hundred and twenty. The total is one thousand one hundred and twenty square centimetres.
Your Turn
An isosceles triangle has base 6 cm and height 4 cm. Find its sloping sides. Check: 32 + 42 = 25, so each is 5 cm.
Watch Out
The height 5 is inside the prism. The sloping faces are 13 cm wide, not 5 cm wide.
Explanation
An open box has no lid, so it has only five faces. The base is eight by five, forty. The front and back are each eight by four, so together sixty four. The two ends are each five by four, so together forty. The total is one hundred and forty four square centimetres. The missing face is the lid, and the lid is the same size as the base. So a closed box would need forty more, one hundred and eighty four. Always check which face is missing before you leave one out.
Your Turn
An open box has a 10 cm × 10 cm base and is 5 cm high. Check: 100 + 4 × 50 = 300 cm2.
Watch Out
Leave out the lid (l × w), not a side. Halving the closed total is not right either.
Explanation
Sometimes you know the surface area and need a length. This box is six by five with an unknown height h, and its surface area is one hundred and forty eight. The top and the bottom are known: two times six times five, sixty. The four sides wrap around the box, so together they are the perimeter of the base, twenty two, times the height: twenty two h. So sixty plus twenty two h equals one hundred and forty eight. Take away sixty: twenty two h equals eighty eight, so h is four centimetres. Check: two times thirty plus twenty four plus twenty is one hundred and forty eight. Quiz and exercises now.
Your Turn
A cube has surface area 96 cm2. Find its edge. Check: 96 ÷ 6 = 16 per face, so the edge is 4 cm.
Watch Out
Subtract the known faces first. 148 ÷ 22 is not the height: the top and bottom are still inside the 148.
📌 Key Points — this lesson in a nutshell
  • Surface area is the total area of every face. Picture the net and add the area of each piece. Units are squared: cm2, m2.
  • A rectangular prism has three pairs of matching faces: SA = 2(lw + lh + wh).
  • A triangular prism has two triangles and three rectangles. Each rectangle is one side of the triangle × the length of the prism.
  • A side you are not given is found with Pythagoras before you can use it: half the base, the height and the slant make a right-angled triangle.
  • An open box has no lid: leave out exactly that face, and only that face.
Step 1: Introduction
Step 1 of 5
A closed box 6 cm × 4 cm × 3 cm 6 cm3 cm4 cm 1top + bottom: 2 × 6 × 4482front + back: 2 × 6 × 3363two ends: 2 × 4 × 324 241824181212 48 + 36 + 24 = 108 cm2Six faces, three matching pairs.SA = 2(lw + lh + wh)
A triangular prism: sides 3, 4, 5 cm, length 10 cm 34510 cm 1two triangles: 2 × ½ × 4 × 3122rectangle 4 × 10403rectangle 3 × 10304rectangle 5 × 10 (sloping)505total132 cm2 Each rectangle isone side of the triangle × 10.Three sides, three rectangles.
Base 24 cm, height 5 cm, length 20 cm 24 cm5?20 cm 1slant2 = 122 + 521692slant = √169133ends: 2 × ½ × 24 × 51204base: 24 × 204805slopes: 2 × 13 × 205206total1120 cm2 Half the base, the height andthe slant make a 5-12-13 triangle.Use the slant, not the height,for the sloping faces.
An open box (no lid) 8 cm × 5 cm × 4 cm 8 cm4 cm5 cmno lid 1base: 8 × 5402front + back: 2 × 8 × 4643two ends: 2 × 5 × 4404total, no lid144 cm25a lid would add 8 × 5+ 40 Five faces, not six.The lid is the same sizeas the base: l × w.
A closed box 6 cm × 5 cm × h cm has SA 148 cm2 6 cmh5 cm 1top + bottom: 2 × 6 × 5602four sides: (6 + 5 + 6 + 5) × h22h360 + 22h = 14822h = 884h = 88 ÷ 224 cm The four sides together arethe perimeter of the base × the height.Quiz and exercises now.
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