Lesson Guide
Explanation
Cut a cylinder open and flatten it and you get two circles and a rectangle. The circles are the top and the bottom, each with area pi r squared. With a radius of three, each is nine pi, so the two together are eighteen pi. The rectangle is the curved surface unrolled. Its height is the height of the cylinder, eight. Its width wrapped all the way around the circle, so it is the circumference, two pi r, which is six pi. Its area is six pi times eight, forty eight pi. The total is eighteen pi plus forty eight pi, which is sixty six pi square centimetres. Leave it in terms of pi: that is the exact answer, and you need no calculator.
Your Turn
Find the surface area of a closed cylinder with r = 1 cm and h = 4 cm. Check: 2π + 8π = 10π cm2.
Watch Out
The rectangle's width is the circumference 2πr, not the radius. 3 × 8 = 24 is not the curved surface.
Explanation
Questions often give the diameter instead of the radius. This cylinder is ten centimetres across, so its radius is five. Halve it first, before anything else. The two circles are two times pi times five squared, which is fifty pi. The curved surface is two pi times five times six, sixty pi. The total is one hundred and ten pi square centimetres. If you use ten as the radius you get three hundred and twenty pi, which is far too big.
Your Turn
Diameter 4 cm, height 3 cm. Check: r = 2, so 8π + 12π = 20π cm2.
Watch Out
Square the radius, not the diameter: π × 52 = 25π, while π × 102 = 100π is four times too much.
Explanation
Real objects are often open. A can with no lid has one circle, not two. With radius four and height ten, the base is sixteen pi and the curved surface is two pi times four times ten, eighty pi, so the can needs ninety six pi square centimetres of metal. A pipe is open at both ends, so it has no circles at all, only the curved surface. With radius two and length fifteen, that is two pi times two times fifteen, sixty pi. Before you add, ask which circles are really there.
Your Turn
A cup with no lid has r = 3 cm and h = 2 cm. Check: 9π + 12π = 21π cm2.
Watch Out
A pipe has no ends. Adding 2 × π × 22 = 8π to the pipe counts two circles that are not there.
Explanation
A composite solid is made of simpler solids joined together. Here a two centimetre cube sits on a six by six by two block. The block on its own has surface area two times thirty six plus twelve plus twelve, one hundred and twenty. The cube on its own has six faces of four, twenty four. But where they touch, two faces disappear: the bottom of the cube, and the patch of the block's top that it covers. That is four plus four, eight. So the surface area is one hundred and twenty plus twenty four minus eight, which is one hundred and thirty six square centimetres. A quicker way to see it: the top of the cube exactly replaces the patch it covers, so you only add the cube's four sides, sixteen.
Your Turn
A 2 cm cube sits on top of a 4 cm cube. Check: 96 + 24 − 8 = 112 cm2, or 96 + 4 × 4 = 112 cm2.
Watch Out
Take away the join twice. Subtracting only 4 gives 140 cm2, which still counts the hidden base of the cube.
Explanation
Here is a two tier cake to ice. The bottom tier has radius five and height two, so on its own it has two circles of twenty five pi and a curved surface of two pi times five times two, twenty pi: seventy pi in all. The top tier has radius three. Its base is hidden, and so is the nine pi patch of the bottom tier underneath it. But its lid is nine pi, exactly the size of the patch it covers. So the top tier only adds its curved surface, two pi times three times two, twelve pi. The total is seventy pi plus twelve pi, which is eighty two pi square centimetres. Quiz and exercises now.
Your Turn
Tiers r = 4, h = 1 and r = 2, h = 1. Check: 32π + 8π + 4π = 44π cm2.
Watch Out
Do not add both tiers whole. 70π + 30π = 100π counts the two hidden 9π circles.
📌 Key Points — this lesson in a nutshell
- Unroll the curved surface of a cylinder and it is a rectangle: its width is the circumference 2πr, so its area is 2πrh.
- A closed cylinder: SA = 2πr2 + 2πrh. Open at one end: πr2 + 2πrh. Open at both ends (a pipe): 2πrh only.
- Halve the diameter first. Leave the answer in terms of π: 18π + 48π = 66π.
- Composite solid: add the surfaces of the parts, then take away both faces at each join: one on each part is hidden.
- When a smaller solid sits on top of a larger one, its top replaces the patch it covers, so you only add its sides.
Step 1: Introduction
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