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Pythagorean Triads and Practical Applications

Maths · Y8 Pythagoras
Year 8
Lesson Guide
Explanation
A Pythagorean triad is a set of three whole numbers that satisfy the theorem, and the largest is always the hypotenuse. The ones worth memorising are 3-4-5, 5-12-13, 8-15-17, 7-24-25, 9-40-41 and 20-21-29. Exam writers use them constantly, because they let a question have a tidy whole-number answer. Recognising 5, 12, 13 saves you the entire calculation. More usefully, it warns you when something has gone wrong — if a question gives you 5 and 12 and you get anything other than 13, you know to look again before you have even checked your working.
Your Turn
A triangle has legs 8 and 15. What is the hypotenuse? Check: 17 — it is a known triad.
Watch Out
Check the numbers really are a triad before trusting it. 5, 12, 14 is not one; the hypotenuse is 13.
Explanation
Triads keep working when you scale them. Double 3-4-5 and you get 6-8-10; triple it and you get 9-12-15; multiply by ten and you get 30-40-50. Check the middle one: 81 plus 144 is 225, which is 15 squared ✓. It works because multiplying every side by the same number keeps the triangle the same shape, just bigger. The real skill is spotting a multiple. If a question gives you legs of 30 and 40, think '3-4-5 times 10' and the answer is 50 with no working at all. Likewise 20 and 48 is 5-12-13 times 4, giving 52.
Your Turn
Legs 15 and 20. Spot the triad. Check: 3-4-5 × 5, so the hypotenuse is 25.
Watch Out
Every side must be scaled by the SAME factor. 3, 4, 10 is not a scaled triad.
Explanation
Here is the theorem doing real work. To check that a corner is square, a builder marks 3 metres up one wall and 4 metres along the other, then measures between the marks. Exactly 5 metres means the corner is a true right angle. More than 5 means it is too open, less than 5 means too closed. This is the theorem running backwards: if three sides satisfy the equation, the angle must be 90 degrees. Builders use 3-4-5, or 6-8-10 for bigger jobs, to square up foundations, decks, fences and tiled floors — no protractor required. It is around two thousand years old and still in use on site this morning.
Your Turn
A builder marks 6 m and 8 m. What should the diagonal measure? Check: 10 m — the 3-4-5 triad doubled.
Watch Out
The measurement must be exact. At 5.2 m the corner is not square, however close it looks.
Explanation
In real problems Pythagoras is usually one step inside something bigger. A yard 12 by 9 metres needs fencing round the edges plus a diagonal path, at 18 dollars a metre. Step one: the diagonal, 144 plus 81 is 225, so 15 metres. Step two: the perimeter, 2 times 21, which is 42 metres. Step three: the total, 42 plus 15, which is 57 metres. Step four: the cost, 57 times 18, which is 1026 dollars. Break these down by asking what you need first and what that lets you find next. Label each step on your page, because examiners award marks per step — a wrong final answer with clear steps still earns most of them.
Your Turn
A 6 m by 8 m yard needs a diagonal path at $20/m. What is the cost? Check: diagonal 10 m, so $200.
Watch Out
Do not round the diagonal early. Carry the exact value into the cost calculation.
Explanation
Here is the whole chapter as a checklist. One: is there a right angle? If not, this is not a Pythagoras question. Two: draw and label, with c opposite the right angle. Three: is the missing side the hypotenuse — yes means add, no means subtract. Four: do you recognise a triad or a multiple of one? Five: substitute, square each number, then combine. Six: take the square root. Seven: sense-check, add units, and re-read the question in case finding the hypotenuse was only step one. Steps three and six are where nearly all the marks are lost, so slow down on those two.
Your Turn
Which two checklist steps cost students the most marks? Check: 3 (add or subtract) and 6 (the square root).
Watch Out
Run the checklist even on easy questions. The habit is what protects you under exam pressure.
📌 Key Points — this lesson in a nutshell
  • A Pythagorean triad is three whole numbers satisfying a2 + b2 = c2; the largest is the hypotenuse.
  • Learn 3-4-5, 5-12-13, 8-15-17, 7-24-25, 9-40-41, 20-21-29.
  • Multiples work too: 6-8-10, 9-12-15, 30-40-50 are all the 3-4-5 triad scaled.
  • Spotting a multiple gives the answer with no working: legs 30 and 40 → 50.
  • The 3-4-5 trick checks a corner is square — the theorem running backwards, used by builders.
  • In practical problems Pythagoras is usually one step: find the diagonal, then the perimeter, then the cost.
  • Label each step — examiners award marks per step.
  • Checklist: right angle? → label → add or subtract? → triad? → square → root → check.
Step 1: Introduction
Step 1 of 5
Whole-number side lengths that work 3, 4, 5 9 + 16 = 25 5, 12, 13 25 + 144 = 169 8, 15, 17 64 + 225 = 289 7, 24, 25 49 + 576 = 625 9, 40, 41 81 + 1600 = 1681 20, 21, 29 400 + 441 = 841 A Pythagorean triad is three whole numbers that satisfy a2 + b2 = c2. The LARGEST is always the hypotenuse. Exams use these constantly. Recognising 5, 12, 13 saves you the whole calculation. More usefully, it warns you when an answer is wrong before you check anything.
Scale a triad and it still works 3, 4, 5 the 3-4-5 triad × 1 6, 8, 10 the 3-4-5 triad × 2 9, 12, 15 the 3-4-5 triad × 3 30, 40, 50 the 3-4-5 triad × 10 Check 9, 12, 15: 81 + 144 = 225 = 152 ✓ Multiplying every side by the same number keeps the triangle the same shape. Spotting a multiple is the real skill. Given 30 and 40, think "3-4-5 × 10" and the answer is 50 with no working.
How builders check a corner is square 4 m along 3 m up measure this The method Mark 3 m up one wall Mark 4 m along the other Measure between the marks exactly 5 m → the corner is square more than 5 m → the corner is too open less than 5 m → too closed This is the theorem running BACKWARDS, used on a building site. If the three sides satisfy a2 + b2 = c2, the angle must be 90°. Builders use 3-4-5 (or 6-8-10 for bigger jobs) to square up foundations, decks, fences and tiled floors — no protractor needed. Two thousand years old, still used on site this morning.
A 12 m by 9 m yard: fence the edges plus a diagonal path 12 m 9 m path 1. Diagonal (Pythagoras) 144 + 81 = 225 → 15 m 2. Perimeter of the yard 2(12 + 9) = 42 m 3. Total length needed 42 + 15 = 57 m 4. Cost at $18 per metre 57 × 18 = $1026 Pythagoras is one step inside a bigger problem. Break it down: what do I need first? What does that let me find next? Label each step on your page. Examiners award marks per step, so a wrong final answer with clear steps still earns most of the marks.
Your Pythagoras checklist 1 Is there a right angle? no right angle → not a Pythagoras question 2 Draw and label: legs a, b; hypotenuse c c is opposite the right angle 3 Is the MISSING side the hypotenuse? yes → ADD · no → SUBTRACT 4 Do I recognise a triad? 3-4-5, 5-12-13, 8-15-17 and their multiples 5 Substitute, square each, then combine square BEFORE adding 6 Take the square root the step most often forgotten 7 Sense-check, add units, re-read the question was the hypotenuse only step one? Steps 3 and 6 are where nearly all the marks are lost. Quiz time!
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