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Finding a Shorter Side

Maths · Y8 Pythagoras
Year 8
Lesson Guide
Explanation
Now the other kind of question: the hypotenuse is known and one leg is missing. With hypotenuse 13 and one leg 5, write a squared plus 5 squared equals 13 squared — the hypotenuse always keeps its place as c. That gives a squared plus 25 equals 169, so a squared is 169 minus 25, which is 144, and a is 12. The rule is that finding a leg means subtracting, because you know the big square and one small square and you want the other small one. Sense-check: a leg must be smaller than the hypotenuse, and 12 is less than 13. If your leg came out bigger than the hypotenuse, you added when you should have subtracted.
Your Turn
Hypotenuse 25, one leg 7. Find the other. Check: 625 − 49 = 576, so a = 24.
Watch Out
The hypotenuse always goes on its own as c2, even when it is the number you were given.
Explanation
Everything in this chapter comes down to one question, asked before you write anything: is the missing side the hypotenuse? If yes, both legs were given, so you add, and your answer will be the biggest side — bigger than either number you started with. If no, the hypotenuse was given, so you subtract, and your answer will be a shorter side, smaller than the hypotenuse. A quick practical test is to look at where the biggest number is. If the biggest number was given to you, subtract. If the biggest number is what you are being asked for, add. Ask this first and the arithmetic looks after itself.
Your Turn
Given sides 10 and 6, where 10 is the hypotenuse. Add or subtract? Check: subtract — 100 − 36 = 64, so 8.
Watch Out
This decision comes first. Adding on a subtract question gives an impossible answer every time.
Explanation
The ladder problem is the classic version of this. A 5 metre ladder has its foot 1.4 metres from a wall — how high does it reach? The ladder is the hypotenuse, because it leans from the ground to the wall, opposite the right angle at the base. So h squared plus 1.96 equals 25, which gives h squared equals 23.04, and h is 4.8 metres. Less than the 5 metre ladder, as it must be. Because the ladder is always the hypotenuse, ladder questions are nearly always subtract questions, unless the ladder's own length is what is missing. Decimals are fine here — just square them carefully, since 1.4 squared is 1.96, not 2.8.
Your Turn
A 10 m ladder is 6 m from the wall. How high does it reach? Check: 100 − 36 = 64, so 8 m.
Watch Out
1.42 = 1.96, not 2.8. Doubling a decimal instead of squaring it is easy to do in a hurry.
Explanation
Isosceles triangles come up constantly, and they need one extra move. With equal sides of 13 and a base of 10, drop the height from the apex — it splits the base exactly in half, making two identical right-angled triangles. Work with just one of them: half the base is 5, and the equal side of 13 becomes that half's hypotenuse. So h squared plus 25 equals 169, h squared is 144, and h is 12. The trap is using the whole base of 10 instead of the half. That would give 169 minus 100, or 69, and a height around 8.3 — completely wrong. Halve the base before substituting, and write 'half base equals 5' on your page so you cannot forget.
Your Turn
Isosceles: equal sides 10, base 12. Find the height. Check: half base 6, so 100 − 36 = 64, h = 8.
Watch Out
Halve the base first. Using the full base is the most common isosceles error by far.
Explanation
Finish every question with three checks that take about ten seconds. First, size: is your leg smaller than the hypotenuse? A leg of 15 with a hypotenuse of 13 is impossible. Second, substitute back: take your three sides and test whether a squared plus b squared really equals c squared — for 5, 12 and 13, 25 plus 144 is 169 ✓. This one is the powerful check, because it catches add-and-subtract mix-ups that nothing else will. Third, units and question: did you answer what was asked, and write the units? '4.8 metres', not a bare '4.8'. Ten seconds of checking is worth more than ten minutes of extra practice.
Your Turn
You get a leg of 8 with hypotenuse 10 and other leg 6. Check it. Check: 36 + 64 = 100 ✓
Watch Out
Substituting back is the only check that catches an add/subtract swap. Do not skip it.
📌 Key Points — this lesson in a nutshell
  • Hypotenuse known, a leg missing → SUBTRACT: a2 = c2 − b2.
  • The hypotenuse always stays as c2, even when it is the number you were given.
  • Decide FIRST: is the missing side the hypotenuse? Yes → add. No → subtract.
  • Quick test: biggest number GIVEN → subtract. Biggest number ASKED FOR → add.
  • A leg must always come out smaller than the hypotenuse.
  • A ladder is always the hypotenuse, so ladder questions are usually subtract questions.
  • Isosceles: drop the height, HALVE the base, then work with one half only.
  • Check by substituting your three sides back into a2 + b2 = c2.
Step 1: Introduction
Step 1 of 5
Hypotenuse 13, one leg 5 — find the other leg 5 a = ? 13 a2 + 52 = 132 the hypotenuse still goes with c a2 + 25 = 169 square each known number a2 = 169 − 25 = 144 SUBTRACT to isolate a a = √144 = 12 square root THE RULE: finding a LEG means SUBTRACT. You know the big square and one small one; you want the other small one. Sense-check: a leg must be SMALLER than the hypotenuse. 12 < 13 ✓ If your "leg" came out bigger than 13, you added when you should have subtracted.
One question decides everything Is the MISSING side the hypotenuse? YES — both legs given ADD c2 = a2 + b2 the answer is the BIGGEST side bigger than either given number NO — hypotenuse given SUBTRACT a2 = c2 − b2 the answer is a SHORTER side smaller than the hypotenuse Practical test: is the BIGGEST number given to you, or being asked for? Given the biggest number → subtract. Asked for the biggest number → add. Ask this BEFORE you write anything, not after.
A 5 m ladder, foot 1.4 m from the wall — how high? 1.4 m h = ? 5 m The LADDER is the hypotenuse it leans across, opposite the right angle h2 + 1.42 = 52 h2 + 1.96 = 25 h2 = 23.04 h = √23.04 = 4.8 m less than the 5 m ladder ✓ The ladder is ALWAYS the hypotenuse. It leans from the ground to the wall, opposite the right angle at the base. So a ladder question is nearly always a SUBTRACT question — unless it asks for the ladder's own length. Decimals are fine: 1.42 = 1.96. Just square carefully — it is not 2.8.
Isosceles: equal sides 13, base 10 — find the height 13 13 5 5 h The height splits the base exactly in half making TWO identical right-angled triangles half the base = 10 ÷ 2 = 5 h2 + 52 = 132 h2 = 169 − 25 = 144 h = 12 work with ONE half only THE TRAP: using the whole base of 10 instead of the half, 5. That gives 169 − 100 = 69 and a height of about 8.3 — completely wrong. Halve the base BEFORE substituting, and write "half base = 5" on your page so you cannot forget. The equal sides become the hypotenuse of each half — so this is a SUBTRACT question.
Three checks that take ten seconds 1. SIZE Is a leg smaller than the hypotenuse? a leg of 15 with a hypotenuse of 13 is impossible 2. SUBSTITUTE BACK Do the three sides satisfy a2 + b2 = c2 ? 25 + 144 = 169 ✓ for 5, 12, 13 3. UNITS & QUESTION Did you answer what was asked, with units? "4.8 m", not a bare "4.8" Check 2 is the powerful one — it catches add/subtract mix-ups. Take your three sides and test the theorem. If it does not balance, you have an error. Ten seconds of checking is worth more than ten minutes of extra practice. Quiz time!
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