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Perimeter and Area, Forwards and in Reverse

Maths · Year 6 Selective
Year 6
Lesson Guide
Explanation
On a rectilinear shape the unlabelled sides are never a mystery: the sides going across must add to the same total as the full width, and the sides going up must add to the full height. Four plus the missing across side makes seven, so it is three; the missing up side plus three makes five, so it is two. Adding all six sides gives twenty-four. There is also a shortcut worth knowing — an L-shape has exactly the same perimeter as the rectangle it fits inside.
Your Turn
A rectilinear shape is 7 wide and 5 tall. What is its perimeter? Check: 2 × (7 + 5) = 24.
Watch Out
The shortcut works for perimeter, not area. The L-shape has a smaller area than its rectangle.
Explanation
Running the area formula backwards is the commonest reverse on this paper. Rectangle P is twelve by five, an area of sixty square centimetres. Rectangle Q has the same area and is four centimetres wide, so its length is sixty divided by four, fifteen. Check by multiplying back. Two rectangles with equal areas can look completely different, which is exactly what makes the question worth asking.
Your Turn
A rectangle has an area of 60 square centimetres and is 4 cm wide. How long is it? Check: 15 cm.
Watch Out
Divide the area by the side you KNOW of the shape you want. Dividing by a side of the other shape is the trap.
Explanation
For a rectangle, half the perimeter is one long side plus one short side, which makes the reverse quick. A perimeter of thirty-four halves to seventeen, and seventeen take twelve leaves five for the short side. The longer route works too — take both twelve-centimetre sides off the thirty-four, leaving ten for the two short sides, five each — and getting the same answer both ways is the check.
Your Turn
A rectangle has perimeter 30 cm and one side 9 cm. Find the other. Check: 15 − 9 = 6 cm.
Watch Out
Halve the perimeter, not the side. Half of 34 is 17, which is one of each side, not one side.
Explanation
Joining an identical rectangle along one side doubles the area, but the perimeter does not double, because two edges end up inside the new shape. A rectangle w by six has perimeter two w plus twelve; side by side they make a two-w by six shape, with perimeter four w plus twelve. So the perimeter grew by two w — and if the question tells you it grew by sixteen centimetres, then w is eight.
Your Turn
Two identical 5 by 3 rectangles are joined along a side of 3. What is the new perimeter? Check: a 10 by 3 shape, so 26.
Watch Out
The perimeter does not double. Two edges of the join disappear inside the shape.
Explanation
A ring between two nested squares is simply the big square minus the one inside it: five by five take four by four is twenty-five take sixteen, nine. Work inwards and the rings go nine, seven, five, three and one — the odd numbers, which add back to twenty-five, and that total is your check. If the question asks for two shaded rings rather than one, work out each and add. Quiz and exercises now.
Your Turn
What is the area of the ring between a 4 by 4 square and a 3 by 3 square? Check: 16 − 9 = 7.
Watch Out
A ring is a subtraction of two areas. Do not try to count its width around the edge.
📌 Key Points — this lesson in a nutshell
  • On a rectilinear shape, the unlabelled sides are the difference of the labelled ones opposite them.
  • The across sides add to the same as the whole width; the up sides add to the same as the whole height.
  • In reverse: side = area ÷ the other side, and for a rectangle side = half the perimeter − the other side.
  • Joining two rectangles adds their areas but the perimeter loses the two joined edges.
Step 1: Introduction
Step 1 of 5
Perimeter of an L-shape 4753?? The two short sides going across must add to the long side: 4 + ? = 7, so the missing across side is 3. The two short sides going up must add to the long side: ? + 3 = 5, so the missing up side is 2. Perimeter = 4 + 2 + 3 + 3 + 7 + 5 = 24 units. Shortcut: the perimeter of any L-shape equals the perimeter of the rectangle it sits in — here 7 + 5 + 7 + 5 = 24.
Rectangle Q has the same area as P 12 cm5 cmP ? cm4 cmQ area of P12 × 560 sq cm60 ÷ 4Q is 15 cm long Work out the area you know, then divide by the side you know of the other shape. P is 12 × 5 = 60 cm2. Q has the same area and is 4 cm wide, so it is 60 ÷ 4 = 15 cm long. Check: 15 × 4 = 60 ✓. Two shapes with the same area can look nothing alike.
Perimeter 34 cm, one side 12 cm 12 cm? perimeter 34half of it1717 − 125 cm Half the perimeter is one long side plus one short side. 34 ÷ 2 = 17, and 17 − 12 = 5 cm for the short side. Or take both long sides off first: 34 − 24 = 10 for the two short sides, so 5 each. The same answer, two ways.
An identical rectangle is attached along one side w6w the joined edge is inside now one rectangle: 2w + 12joined pair: 4w + 12grew by 2wgrew by 16w = 8 Joining two rectangles doubles the area, but the perimeter does NOT double — two edges go inside. One rectangle w by 6 has perimeter 2w + 12. Side by side they make a 2w by 6, with perimeter 4w + 12. So the perimeter grew by 2w. If the question says it grew by 16 cm, then w = 8 cm.
Nested squares — the shaded ring outer 5 × 5 = 25inner 4 × 4 = 16undefinedring9 squares A ring is the big square take the one inside it. 5 × 5 − 4 × 4 = 25 − 16 = 9. The next ring in is 16 − 9 = 7, then 9 − 4 = 5, then 4 − 1 = 3. The rings go 9, 7, 5, 3, 1 — odd numbers, and they add back to 25. Quiz and exercises now.
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