T

Probability and Counting Arrangements

Maths · HAST Middle Secondary
Years 8–9
Lesson Guide
Explanation
To count possibilities, draw a slot for each position, write in how many choices that slot has, and multiply. A four-digit code where each digit can be anything from nought to nine has ten choices in every slot, so the number of codes is ten times ten times ten times ten, which is ten thousand. Multiply rather than add, because every choice in the first slot can pair with every choice in the second. Adding would give forty, which answers no question anyone asked.
Your Turn
How many three-digit codes using digits 0–9 with repeats? Check: 10 × 10 × 10 = 1000.
Watch Out
Digits run 0 to 9, which is TEN choices, not nine. Counting from 1 loses a whole digit.
Explanation
Now the same four digits, but each used exactly once. Once a digit has been placed it is no longer available, so each slot has one fewer choice than the one before: four, then three, then two, then only one left. Four times three times two times one is twenty-four. Notice that the digits are the same but the answer went from ten thousand to twenty-four, and the only thing that changed was whether repeats are allowed. That is what to read for.
Your Turn
How many ways can 3 different books be ordered on a shelf? Check: 3 × 2 × 1 = 6.
Watch Out
Repeats allowed → same number every slot. Each used once → count down. Two very different answers.
Explanation
If multiplying feels like a trick, draw a small tree. Three slots with two choices each: the first split gives two branches, each of those splits into two, and each of those splits again. Eight endings. The tree makes it obvious why you multiply — every existing branch splits again, so the count doubles at each level rather than growing by two. Drawing the tree is only practical for small numbers, but doing it once makes the multiplying rule stick.
Your Turn
Two slots with 3 choices each — how many endings? Check: 3 × 3 = 9.
Watch Out
Trees get huge fast. Use one to understand the rule, then multiply instead of drawing.
Explanation
Chance is how many outcomes you want divided by how many are possible, so the counting always comes first. Exactly one code is correct and ten thousand are possible, so a random guess has a chance of one in ten thousand. If you know the digits but not their order, only twenty-four are possible, so the chance is one in twenty-four — knowing which digits are used makes a guess roughly four hundred times more likely to work. Count the possibilities, and the chance falls out of the count.
Your Turn
One winning ticket out of 250 sold. What is the chance? Check: 1 in 250.
Watch Out
The denominator is how many are POSSIBLE, not how many you tried. Guessing twice does not change it.
Explanation
Often more than one outcome suits you. If three of the twelve possibilities count as a win, the chance is three in twelve, which simplifies to one in four. Count what you want on top and everything possible underneath, then simplify, because the options are usually written in the simplest form and your unsimplified answer may not appear. One in four and three in twelve are the same chance written two ways, so if your answer is not listed, try simplifying it before assuming you are wrong. Quiz and exercises now.
Your Turn
5 of 20 marbles are blue. What is the chance of drawing blue? Check: 5 in 20, which is 1 in 4.
Watch Out
If your answer is not among the options, simplify it before starting again. It may already be there.
📌 Key Points — this lesson in a nutshell
  • Count the possibilities slot by slot and multiply: 10 × 10 × 10 × 10 = 10 000.
  • If items can repeat, every slot has the same number of choices.
  • If each item is used once only, the choices shrink: 4 × 3 × 2 × 1 = 24.
  • Chance is how many you want, out of how many are possible.
Step 1: Introduction
Step 1 of 5
A four-digit code, digits 0–9, repeats allowed 10 choices× 10 choices× 10 choices× 10 choices10 × 10 × 10 × 10 = 10 000 possible codes Each slot can be any of 10 digits, and the slots are independent. So the number of codes is 10 × 10 × 10 × 10 = 10 000, not 10 + 10 + 10 + 10. Multiply, because every choice in one slot pairs with every choice in the next. Adding gives 40, which is the answer to a question nobody asked.
The digits 1, 2, 3 and 4, each used once 4 choices× 3 choices× 2 choices× 1 choices4 × 3 × 2 × 1 = 24 arrangements Once a digit is used it is gone, so each slot has one fewer choice than the last. 4 choices, then 3, then 2, then only 1 left: 4 × 3 × 2 × 1 = 24. Same four digits, but 24 arrangements rather than 10 000 codes. The only thing that changed is whether repeats are allowed. Read for that word.
Three slots, two choices each 2 ways 2 ways 2 ways8 endings altogether 2 × 2 × 2 = 8 endings — and the tree shows why multiplying is right. Every branch splits again, so the count doubles at each level rather than growing by 2.
One correct code out of 10 000 1 wanted out of 10 000 possible a chance of 1 in 10 000 Chance = how many outcomes you want ÷ how many are possible. Exactly one code is correct, and there are 10 000 possible, so the chance is 1 in 10 000. With the digits known but shuffled, only 24 are possible, so the chance is 1 in 24. Knowing which digits are used makes a guess about 400 times more likely to work. Count the possibilities first. The chance falls out of that count.
Wanting any one of several outcomes 3 wanted out of 12 possible a chance of 3 in 12 If 3 of the 12 possibilities suit you, the chance is 3 in 12 — that is 1 in 4. Count the ones you want on top, and everything possible underneath. Then simplify, because options are often written in the simplest form. "1 in 4" and "3 in 12" are the same chance written two ways, so check both forms. Slots and multiply · repeats or not · wanted over possible · simplify. Quiz and exercises now.
Was this lesson helpful? Rate this Course
Discussion
Loading comments...