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Index Laws with Numerical and Algebraic Bases

Maths · Year 9
Year 9
Lesson Guide
Explanation
When you multiply powers of the same base, add the indices. Two cubed times two to the four means three twos multiplied by four more twos: seven twos altogether, so it is two to the seven. With numbers in front, multiply the numbers as usual and add the indices of each letter separately. Three a squared b times four a cubed b to the five: three times four is twelve, a squared times a cubed is a to the five, and b, which means b to the one, times b to the five is b to the six. The answer is twelve a to the five b to the six.
Your Turn
Simplify 5x3 × 2x6. Check: 10x9.
Watch Out
Keep the base. 23 × 24 is 27, not 47 — you add the indices, you never multiply the bases.
Explanation
When you divide powers of the same base, subtract the indices. Five to the seven divided by five cubed: write it as a fraction, and the three fives on the bottom cancel three of the seven fives on top, leaving five to the four. Seven take away three is four. With numbers in front, divide the numbers and subtract the indices letter by letter. Twenty m to the eight n to the five, divided by four m cubed n squared: twenty divided by four is five, m to the eight take away three is m to the five, and n to the five take away two is n cubed. The answer is five m to the five n cubed.
Your Turn
Simplify 18y9 ÷ 6y4. Check: 3y5.
Watch Out
The numbers in front divide: 20m8 ÷ 4m3 is 5m5, not 16m5.
Explanation
A power of a power means repeat. x to the four, all cubed, is x to the four times x to the four times x to the four. Adding the indices gives four plus four plus four, which is twelve, and that is just four times three. So for a power of a power, multiply the indices: x to the four, all cubed, is x to the twelve. Compare that with x to the four times x cubed, with no brackets, which is x to the seven.
Your Turn
Simplify (k5)2. Check: k10.
Watch Out
(x4)3 is x12, not x7. A power outside a bracket means multiply the indices.
Explanation
When a bracket holds a product, the power outside applies to every factor inside. Two a cubed, all to the four, is two to the four times a cubed to the four. Two to the four is sixteen, and a cubed to the four is a to the twelve, so the answer is sixteen a to the twelve. A fraction works the same way: x squared over three, all cubed, is x to the six over twenty-seven, because both the top and the bottom are cubed.
Your Turn
Simplify (3p2q)3. Check: 27p6q3.
Watch Out
Raise the number too. (2a3)4 is 16a12, not 2a12 and not 8a12.
Explanation
Anything divided by itself is one, so seven cubed divided by seven cubed is one. Subtract the indices instead and you get seven to the zero. Both ways must agree, so seven to the zero is one, and the same is true for any base except zero. Be careful with what the index touches. In five x to the zero, only the x is raised to zero, so it is five times one, which is five. In five x in brackets to the zero, the whole bracket is raised, so it is one. Quiz and exercises now.
Your Turn
Work out 4y0 + (4y)0. Check: 4 + 1 = 5.
Watch Out
x0 is 1, not 0. And 5x0 is 5, because the zero index touches only the x.
📌 Key Points — this lesson in a nutshell
  • Same base: when you multiply, add the indices; when you divide, subtract them. Numbers in front multiply or divide as usual.
  • A power of a power: multiply the indices — (x4)3 = x12.
  • A power outside a bracket applies to every factor inside, the number included: (2a3)4 = 16a12.
  • Any non-zero base to the power 0 is 1. The index only touches what it sits on, so 5x0 = 5 but (5x)0 = 1.
Step 1: Introduction
Step 1 of 5
Multiplying powers: add the indices 1write 23 × 24 out in full(2×2×2) × (2×2×2×2)2count the 2s7 of them: 273with numbers in front: 3a2b × 4a3b53 × 4 = 124add the indices letter by letter12a5b6 Same base: keep the base, add the indices.Numbers in front multiply as normal: 3 × 4 = 12.b means b1, so b × b5 = b6.
Dividing powers: subtract the indices 157 ÷ 53: three 5s cancel top and bottom54220m8n5 ÷ 4m3n2: divide the numbers20 ÷ 4 = 53subtract the indices of mm8 ÷ m3 = m54subtract the indices of nn5 ÷ n2 = n3 20m8n5 ÷ 4m3n2 = 5m5n3Divide the numbers in front; subtract the indices.Never subtract the numbers in front: 20 ÷ 4, not 20 − 4.
(x4)3: multiply the indices 1(x4)3 means three lots of x4x4 × x4 × x42add the indices4 + 4 + 4 = 123which is the same as4 × 3 = 124so(x4)3 = x12 Power of a power: multiply the indices.Brackets mean repeat: (x4)3 is x4 three times.Compare x4 × x3 = x7 — no brackets, so add.
(2a3)4 and (x2/3)3 1everything inside the bracket is raised24 × (a3)42the number24 = 163the letter(a3)4 = a124a fraction: raise the top and the bottom(x2/3)3 = x6/27 (2a3)4 = 16a12Every factor inside the bracket gets the power — the number too.24 is 16, not 2 × 4 = 8.
The zero index: a0 = 1 1anything divided by itself73 ÷ 73 = 12subtract the indices instead73 ÷ 73 = 703both must agree70 = 14careful with brackets5x0 = 5, (5x)0 = 1 Any non-zero base to the power 0 is 1.The index only touches what it sits on: in 5x0 only x is raised.Quiz and exercises now.
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