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Mean, Median and Mode

Maths · Y8 Data Analysis
Year 8
Lesson Guide
Explanation
There are three kinds of average, and they measure different things. The mean is what most people picture: add every value and divide by how many there are. For 4, 7, 7, 9 and 13 that is 40 divided by 5, which is 8. The median is the middle value once the data is sorted, which here is 7. And the mode is the value appearing most often, also 7 since it occurs twice. All three get called 'the average' in ordinary speech, but in maths they are three different numbers — here 8, 7 and 7 — so read the question carefully because it will name the one it wants. A memory hook: mode and most both start with M-O.
Your Turn
Find the mean of 2, 4, 6, 8. Check: 20 ÷ 4 = 5.
Watch Out
Divide by how many VALUES there are, not by the largest value.
Explanation
The median needs one step before anything else: sort the data. With an odd number of values, one sits exactly in the middle — sorting 9, 4, 13, 7, 7 gives 4, 7, 7, 9, 13, so the median is 7. With an even number there is no single middle, so average the middle two: sorting 10, 3, 8, 5 gives 3, 5, 8, 10, and the median is 5 plus 8 over 2, which is 6.5. The number one error in this whole topic is forgetting to sort, which would give 13 instead of 7 in that first example. Write the sorted list out rather than sorting in your head. And note the median can be a value not in the data at all, like 6.5 — that is perfectly correct.
Your Turn
Find the median of 12, 5, 9, 3. Check: sorted 3, 5, 9, 12 → (5 + 9) ÷ 2 = 7.
Watch Out
SORT FIRST, every time. Cross values off from each end in pairs to land on the middle.
Explanation
The mode is the value that appears most often, and it behaves differently from the other two. A set can have one mode, as in 3, 5, 5, 7, 9 where the mode is 5. It can have two, like 2, 2, 5, 8, 8, 9, which is called bimodal and both values are modes. It can have none at all, as in 1, 4, 6, 9, 12 where nothing repeats — 'no mode' is a valid answer and you should not invent one. And crucially, the mode is the only average that works on categorical data. You cannot average eye colours, but you can name the most common one. That makes it the right choice when the data is words rather than numbers.
Your Turn
Find the mode of 4, 4, 7, 9, 9, 11. Check: bimodal — 4 and 9.
Watch Out
A set with nothing repeated has NO mode. Writing "the mode is 1" because it comes first is wrong.
Explanation
Data usually arrives as a frequency table, which changes how you calculate. For the mean you cannot just add the pets column and divide by 5 — you need an extra column of value times frequency. That gives 0, 8, 10, 6 and 4, totalling 28 pets among 20 students, so the mean is 28 divided by 20, which is 1.4 pets. For the median with 20 values you need the average of the 10th and 11th. Counting down the frequencies, the first 4 students have 0 pets and the next 8 take you to the 12th student, so both the 10th and 11th have 1 pet, making the median 1. The mode is easiest: the largest frequency is 8, so the mode is 1 pet.
Your Turn
A mean of 1.4 pets — can a student own 1.4 pets? Check: no, but the mean need not be a possible value.
Watch Out
Divide by the TOTAL FREQUENCY (20), not the number of rows (5). This is the classic table error.
Explanation
Choosing the right average matters. Take five house prices of 2, 3, 4, 5 and 86 hundred thousand. The mean is 100 divided by 5, which is 20 — but four of the five houses cost far less than that, so the mean describes none of them. The median is 4, with two houses above and two below, which is a fair description of the group. The difference is that 86 is an outlier, a value far from the rest, and the mean uses every value so one extreme number pulls it hard, while the median only cares about position. So use the mean when there are no outliers, the median when there are outliers or the data is skewed, and the mode for categorical data or when you want the most popular value.
Your Turn
Which average would a real estate agent quote for house prices, and why? Check: the median — a few mansions distort the mean.
Watch Out
When someone quotes "the average", ask which one. The choice can be made to flatter the data.
📌 Key Points — this lesson in a nutshell
  • MEAN = add all values ÷ how many values.
  • MEDIAN = the middle value after SORTING. Even number of values → average the middle two.
  • MODE = the most frequent value. It is the only average that works on categorical data.
  • Forgetting to sort before finding the median is the number one error.
  • The median can be a value not in the data (6.5). That is fine.
  • A set can have one mode, two (bimodal), or no mode at all.
  • From a frequency table: mean = Σ(value × frequency) ÷ total frequency.
  • Divide by the TOTAL FREQUENCY, not the number of rows.
  • An outlier drags the mean but barely moves the median.
  • Use mean when there are no outliers, median when there are, mode for categorical data.
Step 1: Introduction
Step 1 of 5
The data set: 4, 7, 7, 9, 13 MEAN add them all, divide by how many (4+7+7+9+13) ÷ 5 = 40 ÷ 5 = 8 the balance point MEDIAN sort them, take the middle one 4, 7, [7], 9, 13 → 7 the middle value MODE the value that appears most often 7 appears twice → 7 the most popular All three are called "the average" in everyday speech. In maths they are three different things, and here they give 8, 7 and 7. Read the question carefully — it will name the one it wants. MODE and MOST both start with MO — that memory hook is worth having.
Sort, then find the middle ODD number of values 9, 4, 13, 7, 7 sort → 4, 7, 7, 9, 13 median = 7 one value sits exactly in the middle EVEN number of values 10, 3, 8, 5 sort → 3, 5, 8, 10 median = (5 + 8) ÷ 2 = 6.5 average the middle TWO THE NUMBER ONE ERROR: forgetting to sort. Taking the middle of 9, 4, 13, 7, 7 as written gives 13. The median is 7. Write the sorted list out — do not sort in your head. The median can be a value that is not in the data at all. 6.5 does not appear in 3, 5, 8, 10 — and that is perfectly correct. Cross values off from each end in pairs to find the middle reliably.
The most frequent value 3, 5, 5, 7, 9 one mode 5 2, 2, 5, 8, 8, 9 TWO modes — bimodal 2 and 8 1, 4, 6, 9, 12 nothing repeats NO mode blue, blue, red, green works for CATEGORICAL data too blue The mode is the ONLY average that works on categorical data. You cannot average eye colours — but you can name the most common one. "No mode" is a valid answer. Do not invent one when nothing repeats.
Pets owned by 20 students Pets Freq Pets × Freq 0 4 0 1 8 8 2 5 10 3 2 6 4 1 4 TOTAL 20 28 MEAN 28 ÷ 20 = 1.4 pets total of all values ÷ number of values MEDIAN 1 pet 20 values → average the 10th and 11th, both 1 MODE 1 pet the largest frequency is 8
Five house prices: 2, 3, 4, 5 and 86 (hundred thousand) MEAN = 100 ÷ 5 = 20 Four of the five houses cost far LESS than the "average". the single 86 dragged it up MEDIAN = 4 Two houses cost more, two less. A fair description of the group. the 86 moved it not at all An OUTLIER is a value far from the rest. It wrecks the mean, not the median. The mean uses every value, so one extreme number pulls it hard. The median only cares about position, so extremes barely matter. Use the MEAN when no outliers, and you want every value counted Use the MEDIAN when there are outliers, or the data is skewed Use the MODE when the data is categorical, or you want the most popular
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