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Area of Trapeziums, Rhombuses and Kites

Maths · Y7 Area
Year 7
Lesson Guide
Explanation
A trapezium has exactly one pair of parallel sides — a wide end and a narrow end that never meet, joined by two slanted sides. Its area formula is a half times the sum of the parallel sides, times the height, and the neatest way to read that is as an average. Add the two parallel sides, halve them to find the average width, then multiply by the height, exactly as you would for a rectangle. For this one, 6 plus 10 is 16, half of that is 8, and 8 times 4 gives 32 square centimetres. Only the parallel sides go inside the bracket. The slanted sides never appear in the formula, and the height is the perpendicular gap between the parallel pair.
Your Turn
A trapezium has parallel sides 4 cm and 8 cm and a height of 3 cm. Find its area. Check: half of 12 is 6, and 6 × 3 = 18 square cm.
Watch Out
Do not put a slanted side into the bracket. Only the two sides that are parallel to each other belong there.
Explanation
The half in the formula is not a random rule, and here is where it comes from. Take your trapezium, make a second identical copy, turn the copy upside down and slot it against the first. The narrow end of one sits beside the wide end of the other, so the two together form a parallelogram whose base is a plus b — here 10 plus 6, which is 16 — with the same height of 4. That parallelogram has an area of 16 times 4, or 64 square centimetres. But you only wanted one trapezium, so halve it: 32 square centimetres. That is exactly the formula, a half times a plus b times h, and if you can picture the pairing you can rebuild it any time you forget.
Your Turn
Two identical trapeziums with parallel sides 5 and 9 and height 6 are paired up. What is the area of one? Check: 14 × 6 = 84, and half of that is 42 square cm.
Watch Out
Forgetting the ½ gives you the area of BOTH copies. If your answer is exactly double, that is what happened.
Explanation
Rhombuses and kites are handled a different way again — through their diagonals, the lines joining opposite corners straight through the middle. A rhombus is a parallelogram with four equal sides, and a kite has two pairs of equal neighbouring sides. What they share is that their diagonals cross at a right angle, and that lets one formula cover both: area is a half times one diagonal times the other. A rhombus with diagonals of 8 and 6 has an area of a half times 48, which is 24 square centimetres. A kite with diagonals of 10 and 7 has an area of a half times 70, which is 35. Different shapes, same two-step calculation.
Your Turn
A kite has diagonals 12 cm and 5 cm. Find its area. Check: 12 × 5 = 60, and half of that is 30 square cm.
Watch Out
Do not feed a side length into this formula. It needs the two DIAGONALS, the lines through the middle.
Explanation
It is worth seeing where that half comes from, because then you will stop dropping it. Draw a rectangle around the rhombus so the box touches all four corners. The box is as wide as one diagonal and as tall as the other, so its area is 8 times 6, which is 48 square centimetres. Now look at the four little corner triangles that sit outside the shape but inside the box — they match the four triangles inside the shape exactly. So the rhombus fills precisely half the box, which is 24 square centimetres. A kite works the same way for the same reason: its diagonals also meet at a right angle. Multiplying the diagonals and stopping gives double the true area.
Your Turn
A rhombus has diagonals 14 cm and 6 cm. What is the area of the box around it, and of the rhombus? Check: box 84, rhombus 42 square cm.
Watch Out
An answer exactly twice the right one nearly always means the ½ was left out. Halve at the end, every time.
Explanation
Here is the whole toolkit in one place: rectangle is length times width, triangle is a half base times height, parallelogram is base times height, trapezium is a half the sum of the parallel sides times height, and rhombus or kite is a half times the two diagonals. The habit that makes this easy is letting the measurements you are given choose the formula, rather than hunting for the shape's name. Given two diagonals, use a half x y. Given parallel sides and a height, use the trapezium formula. And when the area is given instead, run it backwards: for a trapezium of area 40 with parallel sides 6 and 10, write 40 equals a half times 16 times h, simplify to 40 equals 8h, and divide to get a height of 5 centimetres.
Your Turn
A rhombus has area 36 square cm and one diagonal of 9 cm. Find the other diagonal. Check: 36 = 4.5y, so y = 8 cm.
Watch Out
Simplify the known part BEFORE dividing. Trying to undo a half and a multiplication in one move is where errors creep in.
📌 Key Points — this lesson in a nutshell
  • A trapezium has exactly one pair of parallel sides.
  • Trapezium: A = ½(a + b) × h — average the two parallel sides, then multiply by the height.
  • The ½ is there because two copies of a trapezium make a parallelogram of base a + b.
  • Only the PARALLEL sides go in the bracket — the slanted sides are never used.
  • A rhombus has 4 equal sides; a kite has 2 pairs of equal neighbouring sides.
  • Rhombus and kite: A = ½ × x × y, where x and y are the two DIAGONALS.
  • That ½ is there because the shape fills exactly half the rectangle drawn around its diagonals.
  • Leaving out either ½ gives exactly double the right answer.
  • h is always the perpendicular gap between the parallel sides, never a slanted side.
  • Working backwards: formula, substitute, simplify the known part, solve, then check forwards.
Step 1: Introduction
Step 1 of 5
One pair of parallel sides — a shape with a wide end and a narrow end a = 6 cm b = 10 cm h = 4 cm the two parallel sides are the ones that never meet A = ½ × (a + b) × h Add the two parallel sides, halve to get their AVERAGE, then multiply by the height. average width × height, just like a rectangle Working this one out 6 + 10 = 16 half of 16 = 8 (the average width) 8 × 4 = 32 A = 32 cm2 Only the PARALLEL sides go inside the bracket. The two slanted sides are not part of the formula at all. And h is the perpendicular gap between the parallel sides, not a slanted side.
Two copies make a parallelogram the trapezium a copy, turned upside down base of the parallelogram = 10 + 6 = 16 cm h = 4 The two copies together make a parallelogram whose base is a + b, with the same height h. Area of the pair = (a + b) × h = 16 × 4 = 64 cm2 But you only wanted ONE so halve it: 64 ÷ 2 = 32 A = ½ × (a + b) × h that is exactly where the ½ comes from Understanding this means you can rebuild the formula if you forget it. Two trapeziums make a parallelogram of base a + b, so one is half of (a + b) × h. Dropping the ½ gives double the answer — 64 instead of 32.
Two shapes, one formula: A = ½ × x × y RHOMBUS — 4 equal sides y = 6 cm x = 8 cm ½ × 8 × 6 = 24 cm2 KITE — 2 pairs of equal neighbouring sides x = 10 cm y = 7 cm ½ × 10 × 7 = 35 cm2 A DIAGONAL joins two opposite corners, straight through the middle. In both these shapes the two diagonals cross at a right angle — that is what makes the formula work.
Draw the box around the diagonals the box is 8 cm wide and 6 cm tall x = 8 cm across y = 6 cm The box has sides equal to the diagonals so its area is x × y = 8 × 6 = 48 cm2 The four corner triangles left OUTSIDE the shape match the four INSIDE it exactly. So the shape is HALF its box half of 48 = 24 cm2 A = ½ × x × y Multiplying the diagonals and stopping gives DOUBLE the real area. That is the most common mistake in this whole topic. Picture the box and you will never leave the ½ out.
Let the given measurements choose the formula Rectangle A = l × w you need: two sides meeting at a corner Triangle A = ½ × b × h you need: base with its perpendicular height Parallelogram A = b × h you need: base with its perpendicular height Trapezium A = ½(a + b) × h you need: the two PARALLEL sides, and h Rhombus or kite A = ½ × x × y you need: the two DIAGONALS WORKING BACKWARDS Trapezium, area 40 cm2, parallel sides 6 and 10. 40 = ½ × 16 × h, so 40 = 8h h = 40 ÷ 8 = 5 cm THE FOUR STEPS 1. write the formula 2. substitute what you know 3. simplify the known part first 4. solve, then check forwards
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